What volume of carbon monoxide 4 is formed by the interaction of 25 g

What volume of carbon monoxide 4 is formed by the interaction of 25 g of sodium carbonate containing 5% impurities with hydrochloric acid.

The reaction of dissolving sodium carbonate in hydrochloric acid is described by the following chemical reaction equation:

Na2CO3 + 2HCl = 2NaCl + CO2 + H2O;

When 1 mol of sodium carbonate is dissolved in acid, 1 mol of gaseous carbon dioxide is synthesized. This consumes 2 mol of hydrochloric acid.

Let’s calculate the chemical amount of a substance contained in 10.6 grams of sodium carbonate.

M Na2CO3 = 23 x 2 + 12 + 16 x 3 = 106 grams / mol;

N Na2CO3 = 25 x 0.95 / 106 = 0.224 mol;

Thus, upon dissolution of 0.224 mol of soda, 0.224 mol of carbon dioxide is synthesized.

Let’s calculate its volume. To do this, we multiply the amount of substance and the standard volume of 1 mole of gaseous substance. 1 mole of ideal gas fills a volume of 22.4 liters under normal conditions.

V CO2 = 0.224 x 22.4 = 5.018 liters;