What volume of carbon monoxide 4 is formed by the interaction of calcium carbonate with hydrochloric
What volume of carbon monoxide 4 is formed by the interaction of calcium carbonate with hydrochloric acid containing HCL in a chemical amount of 0.2 mol.
The dissolution reaction of limestone in hydrochloric acid is described by the following chemical reaction equation:
CaCO3 + 2HCl = CaCl2 + CO2 + H2O;
When 1 mol of limestone is dissolved in acid, 1 mol of gaseous carbon dioxide is synthesized. This consumes 2 mol of hydrochloric acid.
Thus, when neutralizing 0.2 mol of acid, 0.1 mol of carbon dioxide is synthesized.
Let’s calculate its volume.
To do this, multiply the amount of the substance and the standard volume of 1 mole of the gaseous substance.
1 mole of ideal gas fills a volume of 22.4 liters under normal conditions.
V CO2 = 0.1 x 22.4 = 2.24 liters;