What volume of carbon monoxide 4 is formed when 784 liters of ethylene C2 H4 are burned?

Let’s execute the solution:

In accordance with the condition of the problem, we write down the equation of the process:

С2Н4 + 3О2 = 2СО2 + 2Н2О + Q – ethylene combustion, carbon dioxide and water are released;

Proportions:
1 mol of gas at normal level – 22.4 liters;

X mol (C2H4) -784 L from here, X mol (C2H4) = 1 * 784 / 22.4 = 35 mol;
35 mol (C2H4) – X mol (O2);
-1 mol -3 mol from here, X mol (O2) = 35 * 3/1 = 105 mol.

Find the volume of the product:
V (CO2) = 105 * 22.4 = 2352 l

Answer: received carbon monoxide (4) with a volume of 2352 l