What volume of carbon monoxide (4) will be obtained when decomposing natural
What volume of carbon monoxide (4) will be obtained when decomposing natural limestone weighing 0.5 kg, containing a mass fraction of calcium carbonate (92%)?
The thermal decomposition reaction of calcium carbonate is described by the following chemical reaction equation:
CaCO3 = CaO + CO2 ↑;
Let’s calculate the chemical amount of calcium carbonate (limestone). To do this, we divide its weight by the mass of 1 mole of the substance.
M CaCO3 = 40 + 12 + 16 x 3 = 100 grams / mol;
N CaCO3 = 500 x 0.92 / 100 = 4.6 mol;
The same molar amount of calcium oxide and carbon dioxide will theoretically be synthesized.
To calculate its volume, you need to multiply the amount of substance by the volume of 1 mole of gas (filling volume 22.4 liters).
V CO2 = 4.6 x 22.4 = 103.04 liters;