What volume of carbon monoxide (4) will be released during the thermal decomposition of 900 g
What volume of carbon monoxide (4) will be released during the thermal decomposition of 900 g of limestone containing 15% of impurities?
The decomposition reaction of limestone is described by the following chemical reaction equation:
CaCO3 = CaO + CO2;
When 1 mol of limestone is decomposed, 1 mol of gaseous carbon dioxide is synthesized.
Let’s calculate the available chemical amount of calcium carbonate substance.
M CaCO3 = 40 + 12 + 16 x 3 = 100 grams / mol;
N CaCO3 = 900 x 0.85 / 100 = 7.65 mol;
During the reaction, the same amount of carbon dioxide will be synthesized.
Let’s calculate its volume.
To do this, multiply the amount of the substance and the standard volume of 1 mole of the gaseous substance.
1 mole of ideal gas fills a volume of 22.4 liters under normal conditions.
V CO2 = 7.65 x 22.4 = 171.36 liters;