What volume of carbon monoxide (IV) can be obtained by reacting with

What volume of carbon monoxide (IV) can be obtained by reacting with an excess of nitric acid 20 g of calcium carbonate containing 3% impurities?

The reaction of dissolving calcium carbonate in nitric acid is described by the following chemical reaction equation:

CaCO3 + 2HNO3 = Ca (NO3) 2 + CO2 + H2O;

When 1 mol of calcium carbonate is dissolved in acid, 1 mol of gaseous carbon dioxide is synthesized. This consumes 2 mol of nitric acid.

Let’s calculate the chemical amount of a substance contained in 53 grams of sodium carbonate.

M CaCO3 = 40 + 12 + 16 x 3 = 100 grams / mol;

N CaCO3 = 20 x 0.97 / 100 = 0.194 mol;

Thus, upon dissolution of 0.194 mol of calcium carbonate, 0.194 mol of carbon dioxide is synthesized.

Let’s calculate its volume.

To do this, multiply the amount of the substance and the standard volume of 1 mole of the gaseous substance.

1 mole of ideal gas fills a volume of 22.4 liters under normal conditions.

V CO2 = 0.194 x 22.4 = 4.346 liters;