What volume of carbon monoxide (lV) will be absorbed under normal conditions

What volume of carbon monoxide (lV) will be absorbed under normal conditions by a solution containing 14.8 g of calcium hydroxide (Ca (OH) 2)

1. Let’s compose the reaction equation:

CO2 + Ca (OH) 2 = CaCO3 + H2O;

2.Calculate the chemical amount of calcium hydroxide:

n (Ca (OH) 2) = m (Ca (OH) 2): M (Ca (OH) 2);

M (Ca (OH) 2) = 40 + 2 * 17 = 74 g / mol;

n (Ca (OH) 2) = 14.8: 74 = 0.2 mol;

3. Determine the amount of absorbed carbon dioxide:

n (CO2) = n (Ca (OH) 2) = 0.2 mol;

V (CO2) = n (CO2) * Vm = 0.2 * 22.4 = 4.48 liters.

Answer: 4.48 liters.



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