What volume of carbon monoxide will be released during the firing of 500 tons of limestone containing

What volume of carbon monoxide will be released during the firing of 500 tons of limestone containing 0.1 mass fraction of impurities?

The limestone roasting reaction is described by the following equation:

CaCO3 = CaO + CO2 ↑;

When decomposing 1 mol of limestone, 1 mol of calcium oxide and 1 mol of carbon monoxide is obtained.

Let’s determine the chemical amount of calcium carbonate. To do this, divide its weight by its molar weight.

M CaCO3 = 40 + 12 + 16 x 3 = 100 grams / mol; N CaCO3 = 500,000,000 x 0.9 / 100 = 4,500,000 mol;

Let’s calculate the volume of 4 500 000 mol of carbon dioxide.

To this end, we multiply the amount of substance by the volume of 1 mole of gas (filling 22.4 liters).

V CO2 = 4,500,000 x 22.4 = 100,800,000 liters = 100,800 m3;