What volume of chlorine will add to ethene weighing 4.2 g?

Let’s implement the solution:
1. Let’s compose the reaction equation:
Н2С = СН2 + Cl2 = CH2Cl – CH2Cl – addition reaction, ethene chlorination occurs, dichloroethane is released;
2. Let’s make calculations: M (C2H4) = 12 * 2 = 4 = 28 g / mol;
Y (C2H4) = m (C2H4) / M (C2H4); Y (C2H4) = 4.2 / 28 = 0.15 mol;
3. Let’s make a proportion according to the reaction equation:
0.15 mol (C2H4) – X mol (Cl2);
-1 mol – 1 mol hence, X mol (Cl2) = 0.15 mol;
4. Let’s calculate the volume of chlorine, applying Avogadro’s law:
V (Cl2) = 0.15 * 22.4 = 3.36 liters.
Answer: to carry out the reaction, chlorine with a volume of 3.36 liters is required.