What volume of chlorine will be required to carry out the chlorination of ethylene if the reaction produces 28 g of 1,2 dichloroethane?

univerkov | December 19, 2020 | education

Given: m (C2H4Cl2) = 28g
Find: V (Cl2) -?
Decision.
H2C = CH2 + Cl2-> H2C (Cl) -H2C (Cl) m = M * n => n = m / M n (C2H4Cl2) = 28/99 = 0.28 mol n (Cl2) = n (C2H4Cl2) V = Vm * n V (Cl2) = 22.4 * 0.28 = 6.272L
Answer: the volume of chlorine is 6.272 liters.

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