What volume of CO2 will be obtained when H2SO4 interacts with 300 g of CaCo3?

univerkov | December 9, 2020 | education

H2SO4 + CaCO3 -> H2O + CO2 + CaSO4 n (CaCO3) = m (CaCO3) / M (CaCO3) = 300g / 100g / mol = 3mol
Since the ratio of substances is 1: 1, then n (CaCO3) = n (CO2) = 3 mol V (CO2) = 22.4 l / mol * 3 mol = 67.2 l

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