What volume of CO2 will be released during alcoholic fermentation of 36g glucose?

Alcoholic fermentation is understood as the anaerobic oxidation of glucose by microorganisms to ethyl alcohol and carbon dioxide. The reaction can be written as an equation:

C6H12O6 = 2 C2H5OH + 2 CO2

Molar mass of glucose = 180 g / mol;

molar volume of carbon dioxide = 22.4 l / mol (according to Avogadro’s law)

Let’s compose the proportion according to the reaction equation:

36 g of glucose corresponds to X l. carbon dioxide like

180 g / mol of glucose corresponds to 2 * 22.4 l / mol of carbon dioxide

X = (36 * 2 * 22.4) / 180 = 8.96 liters.

Answer: 8.96 liters. carbon dioxide.