What volume of ethylene is released when heating ethyl alcohol with a mass of 23 g?

Let’s write the reaction equation:

C2H5OH (t, cat.) = C2H4 + H2O

Let’s find the amount of the substance C2H5OH:

v (C2H5OH) = m (C2H5OH) / M (C2H5OH) = 23/46 = 0.5 (mol).

According to the reaction equation, from 1 mol of C2H5OH 1 mol of C2H4 is formed, therefore:

v (C2H4) = v (C2H5OH) = 0.5 (mol).

Thus, the volume of ethylene obtained, measured under normal conditions (n.o.):

V (C2H4) = v (C2H4) * Vm = 0.5 * 22.4 = 11.2 (l).

Answer: 11.2 l.