What volume of gas is formed by the interaction of 0.2 mol of sodium carbonate and 0.5 mol of sulfuric acid?

The reaction of sodium carbonate dissolution in sulfuric acid is described by the following chemical reaction equation:
Na2CO3 + H2SO4 = Na2SO4 + CO2 + H2O;
When 1 mol of sodium carbonate is dissolved in acid, 1 mol of gaseous carbon dioxide is synthesized. This consumes 1 mol of sulfuric acid.
Thus, when 0.2 mol of soda is dissolved, 0.2 mol of carbon dioxide is synthesized.
This will consume 0.2 mol of acid.
Let’s calculate its volume. To do this, we multiply the amount of substance and the standard volume of 1 mole of gaseous substance.
1 mole of ideal gas fills a volume of 22.4 liters under normal conditions.
V CO2 = 0.2 x 22.4 = 4.48 liters;

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