What volume of gas is formed by the interaction of 42 g of sulfur with hydrogen?

univerkov | December 3, 2020 | education

H2 + S = H2S
n (S) = m \ M = 42 \ 32 = 1.31 mol
by ur-th reaction n (H2S) = n (S) = 1.31 mol
V (H2S) = n * Vm = 1.31 * 22.4 = 29.34 l
Answer: V (H2S) = 29.34 l

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