What volume of gas is formed by the interaction of a 200 g nitric acid solution with a 0.315 mass fraction

What volume of gas is formed by the interaction of a 200 g nitric acid solution with a 0.315 mass fraction of acid with potassium sulfide?

1. The interaction of nitric acid with potassium sulfide proceeds according to the equation:

2HNO3 + K2S = 2KNO3 + H2S ↑;

2. find the mass of nitric acid:

m (HNO3) = w (HNO3) * m (solution) = 0.315 * 200 = 63 g;

3.Calculate the chemical amounts of nitric acid and the resulting hydrogen sulfide:

n (HNO3) = m (HNO3): M (HNO3);

M (HNO3) = 1 + 14 + 3 * 16 = 63 g / mol;

n (HNO3) = 63: 63 = 1 mol;

n (H2S) = n (HNO3): 2 = 1: 2 = 0.5 mol;

4. calculate the volume of hydrogen sulfide:

V (H2S) = n (H2S) * Vm = 0.5 * 22.4 = 11.2 liters.

Answer: 11.2 liters.