What volume of gas will be released as a result of the final dissolution of calcium carbonate

What volume of gas will be released as a result of the final dissolution of calcium carbonate weighing 20 g in chloride acid?

The reaction of dissolving chalk in hydrochloric acid is described by the following chemical reaction equation:

CaCO3 + 2HCl = CaCl2 + CO2 + H2O;

When 1 mol of chalk is dissolved in acid, 1 mol of gaseous carbon dioxide is synthesized. This consumes 2 mol of hydrochloric acid.

Let’s calculate the available chemical amount of calcium carbonate substance.

M CaCO3 = 40 + 12 + 16 x 3 = 100 grams / mol;

N CaCO3 = 20/100 = 0.2 mol;

Thus, upon dissolution of 0.2 mol of limestone, 0.2 mol of carbon dioxide is synthesized.

Let’s calculate its volume. To do this, multiply the amount of the substance and the standard volume of 1 mole of the gaseous substance. 1 mole of ideal gas fills a volume of 22.4 liters under normal conditions.

V CO2 = 0.2 x 22.4 = 4.48 liters;