What volume of gas will be released when 0.1 mol of glycerin interacts with sodium?

Decision:
Let’s write the reaction equation:
2HO – CH2 – CHOH – CH2OH + 6Na = 2Na – O – CH2 – CH (ONa) – CH2ONa + 3H2 – substitution reaction, hydrogen gas is released;
Determine the molar mass of glycerin:
Let’s make a proportion according to the equation:
0.1 mol C3H5 (OH) 3 – X mol (H2);
-2 mol                           -3 mol from here, X mol (H2) = 0.1 * 3/2 = 0.15 mol;
Let’s calculate the volume of hydrogen using Avogadro’s law:
V (H2) = 0.15 * 22.4 = 3.36 liters.
Answer: when glycerin interacts with sodium, hydrogen was released in a volume of 3.36 liters.