What volume of gas will be released when 6.5 g of zinc react with 19.6 g of sulfuric acid?

univerkov | May 27, 2021 | education

Zn + H2SO4 (diluted) = ZnSO4 + H2 ↑

First, you need to remember the formulas necessary for solving: n = m / M. n = V / Vm. V = n * Vm.
n (Zn) = 6.5g / 65g / mol = 0.1 mol
n (Zn) = n (H2), therefore, they are equal to 0.1 mol both

V (H2) = 0.1 mol x 22.4 L / mol = 2.24 L

Answer: v (H2) = 2.24 l

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