What volume of gas will be released when 784 g of 5% sulfuric acid solution acts on excess zinc?

The reaction between zinc and sulfuric acid is described by the following chemical reaction equation.

Zn + H2SO4 = ZnSO4 + H2;

1 mole of metal reacts with 1 mole of acid. In this case, 1 mol of salt is synthesized and 1 mol of gaseous hydrogen is released.

The mass of sulfuric acid is 784 x 0.05 = 39.2 grams.

Let’s calculate the chemical amount of a substance in 39.2 grams of acid.

M H2SO4 = 2 + 32 + 64 = 98 grams / mol;

N H2SO4 = 39.2 / 98 = 0.4 mol;

When interacting with 0.4 mol of acid, 0.4 mol of hydrogen will be released.

Let’s calculate its volume.

One liter of ideal gas under normal conditions assumes a volume of 22.4 liters

V H2 = 0.4 x 22.4 = 8.96 liters;