What volume of gas will be released when a 40% solution of hydrochloric acid weighing 40 g

| June 2, 2021 | education

What volume of gas will be released when a 40% solution of hydrochloric acid weighing 40 g interacts with calcium carbonate?

Find the mass of hydrochloric acid in the solution.

W = m (substance): m (solution) × 100%,

hence m (substance) = (m (solution) × w): 100%.

m (substance) = (40 g × 40%): 100% = 16 g.

Find the amount of HCl.

n = m: M.

М (HCl) = 36.5 g / mol.

n = 16 g: 36.5 g / mol = 0.438 mol.

Let’s find the quantitative ratios of substances.

CaCO3 + 2HCl → CaCl2 + H2O + CO2 ↑.

For 2 mol of HCl, there is 1 mol of CO2.

Substances are in quantitative ratios of 2: 1.

The amount of CO2 substance is 2 times less than that of HCl.

n (CO2) = ½ n (HCl) = 0.438: 2 = 0.219 mol.

Let’s find the volume of CO2.

V = Vn n, where Vn is the molar volume of gas, equal to 22.4 l / mol, and n is the amount of substance.

V = 0.219 mol × 22.4 L / mol = 4.91 L.

Answer: 4.91 liters.



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