What volume of gas will be released when an excess of sulfuric acid acts on chalk weighing 30 grams?

univerkov | February 5, 2021 | education

1. Let’s write the reaction equation:

CaCO3 + H2SO4 = CaSO4 + H2O + CO2.

2. Find the amount of calcium carbonate:

n (CaCO3) = m (CaCO3) / M (CaCO3) = 30 g / 100 g / mol = 0.3 mol.

3. Using the equation, we find the amount of carbon dioxide and its volume (Vm is the molar volume, constant equal to 22.4 l / mol):

n (CO2) = n (CaCO3) = 0.3 mol.

V (CO2) = n (CO2) * Vm = 0.3 mol * 22.4 l / mol = 6.72 l.

Answer: V (CO2) = 6.72 liters.

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