What volume of gas will be released when dissolving 9.6 grams of magnesium in hydrochloric acid?

Let’s compose the equation for the reaction of interaction of magnesium with hydrochloric acid:
Mg + 2HCl = MgCl2 + H2;

The molecular weight of magnesium is 24 g / mol. Let’s find the amount of a substance in magnesium:
9.6 / 24 = 0.4 mol;

Gas (hydrogen) is preceded by the same coefficient as magnesium. This means that the amount of substance in hydrogen is 0.4 mol. Let’s find the volume of hydrogen:
0.4 * 22.4 = 8.96 liters;

Answer: the volume of hydrogen is 8.96 liters.



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