What volume of gas will be released when draining 150 g of 30% hydrochloric acid with sodium carbonate

What volume of gas will be released when draining 150 g of 30% hydrochloric acid with sodium carbonate solution containing 0.5 mol of this salt?

The reaction of dissolving sodium carbonate in hydrochloric acid is described by the following chemical reaction equation:

Na2CO3 + 2HCl = 2NaCl + CO2 + H2O;

When 1 mol of sodium carbonate is dissolved in acid, 1 mol of gaseous carbon dioxide is synthesized. This consumes 2 mol of hydrochloric acid.

Let’s calculate the chemical amount of a substance contained in 150 grams of a 30% hydrochloric acid solution.

M HCl = 1 + 35.5 = 36.5 grams / mol;

N HCl = 150 x 0.3 / 36.5 = 1.233 mol;

Thus, when 0.5 mol of soda is dissolved, 0.5 mol of carbon dioxide is synthesized. This requires 1 mol of acid.

Let’s calculate the volume of carbon dioxide. To do this, we multiply the amount of substance and the standard volume of 1 mole of gaseous substance. 1 mole of ideal gas fills a volume of 22.4 liters under normal conditions.

V CO2 = 1 x 22.4 = 22.4 liters;