What volume of H2 is formed when 130 g of zinc is dissolved in hydrochloric acid?

Zinc interacts with hydrochloric (hydrochloric) acid to release hydrogen gas. This synthesis is described by the following chemical reaction equation.

Zn + 2HCl = ZnCl2 + H2;

1 mole of metallic zinc reacts with 2 moles of hydrochloric acid. In this case, 1 mol of zinc chloride is synthesized and 1 mol of gaseous hydrogen is released.

Let’s calculate the chemical amount of a substance in 130 grams of zinc.

To do this, divide the weight of zinc by its molar weight, which is 65 grams / mol.

M Zn = 65 grams / mol;

N Zn = 130/65 = 2 mol;

The same amount of hydrogen will be synthesized.

Let’s calculate its volume.

To do this, multiply the amount of substance in mol by the volume of 1 mol of ideal gas under normal conditions (22.4 liters).

V H2 = 2 x 22.4 = 44.8 liters;