What volume of H2 is formed when 325 g of Zn is dissolved in HCl?

1. The dissolution of zinc in hydrochloric acid is described by the reaction equation:

2HCl + Zn = ZnCl2 + H2 ↑;

2.Calculate the chemical amount of zinc:

n (Zn) = m (Zn): M (Zn) = 325: 65 = 5 mol;

3. Determine the amount of generated hydrogen:

n (H2) = n (Zn) = 5 mol;

4.calculate the volume of hydrogen:

V (H2) = n (H2) * Vm = 5 * 22.4 = 112 HP

Answer: 112 l.