What volume of hydrogen (at 0º and 760 mm Hg) will be released when 1 kg of aluminum is dissolved in acid?

Aluminum reacts with hydrochloric acid. In this case, an aluminum chloride salt is formed and elemental hydrogen is released. The interaction is described by the following chemical equation.

Al + 3HCl = AlCl3 + 3/2 H2;

Let’s calculate the chemical amount of aluminum. For this purpose, we divide its weight by the molar weight of the substance.

M Al = 27 grams / mol;

N Al = 1000/27 = 37.16 mol;

Regardless of which acid is used, the chemical amount of released hydrogen will be: 37.16 x 3/2 = 55.74 mol

Let’s define its volume.

To do this, we multiply the chemical amount of the substance by the volume of 1 mole of gas (filling a space with a volume of 22.4 liters).

V H2 = 55.74 x 22.4 = 1249 liters;