What volume of hydrogen can be obtained if 13 g of zinc is chilled in 20 ml of a 15%

What volume of hydrogen can be obtained if 13 g of zinc is chilled in 20 ml of a 15% solution of hydrochloric acid with a density of 1.07 g / ml.

The reaction of zinc with hydrochloric acid is described by the following chemical reaction equation:

Zn + 2HCl = ZnCl2 + H2;

Let’s calculate the chemical amount of hydrogen chloride. To do this, we divide its weight by the mass of 1 mole of the substance.

M HCl = 1 + 35.5 = 36.5 grams / mol;

N HCl = 20 x 0.15 x 1.07 / 36.5 = 0.0879 mol;

Let’s calculate the chemical amount of metallic zinc. To do this, we divide its weight by the mass of 1 mole of metal.

N Zn = 13/65 = 0.2 mol;

With 0.0879 mol of acid, 0.0879 / 2 = 0.0439 mol of zinc will react. This will receive 0.0439 mol of hydrogen and 0.0439 mol of zinc chloride. Let’s determine the volume of hydrogen. To this end, we multiply the amount of substance by the volume of 1 mole of gas (22.4 liters).

V H2 = 0.0439 x 22.4 = 0.9834 liters;