What volume of hydrogen can be released under the action of formic acid on 52 g

What volume of hydrogen can be released under the action of formic acid on 52 g of technical iron, the mass fraction of impurities in which is 10%

Let us write down the reaction equations for this problem.

2HCOOH + Fe = (HCOO) 2Fe + H2.

Let’s determine the mass of pure iron.

100% – 10% = 90%.

52 g of iron is 100%.

X g of iron is 90%.

X = 52 * 90/100 = 46.8%.

Let’s determine the amount of iron substance.

M (Fe) = 56 g / mol.

n (Fe) = 46.8 g / 56 g / mol = 0.84 mol.

Further, according to the reaction equation, we determine the amount of hydrogen substance.

0.84 mol iron – x mol hydrogen.

1 mol – 1 mol.

X = 0.84 mol.

Next, let’s determine the volume of hydrogen.

V = n * Vm = 0.84 mol * 22.4 l / mol = 18.7 l.

Answer: the volume of hydrogen is 18.7 liters.