What volume of hydrogen (H2) is formed by the interaction of 50 g of 9.8% sulfuric acid (H2SO4) solution with zinc?

Zinc metal reacts with sulfuric acid to release hydrogen gas and form zinc sulfate (zinc sulfate). The synthesis is described by the following equation:

Zn + H2SO4 = ZnSO4 + H2;

The metal reacts with acid in equal molar amounts. During the reaction, the same amounts of salt and hydrogen are synthesized.

Let’s calculate the available chemical amount of sulfuric acid. To do this, divide its weight by the weight of 1 mole of acid.

M H2SO4 = 2 + 32 + 16 x 4 = 98 grams / mol; N H2SO4 = 50 x 0.098 / 98 = 0.05 mol;

The same amount of hydrogen and zinc sulfate (zinc sulfate) will be synthesized.

Let’s calculate the volume of this amount of hydrogen gas. To do this, multiply the amount of substance by the volume of 1 mole of ideal gas (22.4 liters).

N H2 = 0.05 mol; V H2 = 0.05 x 22.4 = 1.12 liters;