When dissolved in acetic acid, the metallic zinc turns into zinc acetate. Zinc is a bivalent metal. Therefore, with a reaction, it interacts with a double amount of acetic acid. The single chemical amount of zinc acetate reaction is described by the following chemical reaction equation:
Zn + 2Sn3Cone = Zn (CH3SOO) 2 + H2;
Calculate the chemical amount of acetic acid. For this purpose, we divide the weight of the acid on the weight of 1 praying of this acid.
M CH3Cone = 60 grams / mole;
N CH3Cone = 150 x 0.12 / 60 = 0.3 mol;
Determine the molar amount of zinc. To do this, we split its weight for a mass of 1 mole of metal.
N zn = 13/65 = 0.2 mol;
With such a number of acid, 0.3 / 2 = 0.15 mol zinc is presented. At the same time, 0.15 mol of hydrogen will be synthesized. Find its volume. To do this, multiply the amount of substance to the volume of 1 praying gas (component of 22.4 liters).
V h2 = 0.15 x 22.4 = 3.36 liters;
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