What volume of hydrogen is formed by the interaction of 1 mol of aluminum with hydrochloric acid?

What volume of hydrogen is formed by the interaction of 1 mol of aluminum with hydrochloric acid? The reaction proceeds according to the equation: 2Al + 6HCl = 2AlCl3 + 3H2

Aluminum enters into an active reaction with hydrochloric acid. At the same time, the salt of aluminum chloride is synthesized and bubbles of hydrogen gas are released. The reaction is described by the following equation.

Al + 3HCl = AlCl3 + 3/2 H2;

N Al = 1 mol;

The chemical amount of released hydrogen will be: 1 x 3/2 = 1.5 mol

Let’s find its volume.

For this purpose, we multiply the chemical amount of the substance by the volume of 1 mole of gas (filling the space with a volume of 22.4 liters).

V H2 = 1.5 x 22.4 = 33.6 liters;