What volume of hydrogen is formed by the interaction of 10.2 g of iron with the required amount of sulfuric acid?

| February 22, 2021 | education

What volume of hydrogen is formed by the interaction of 10.2 g of iron with the required amount of sulfuric acid? What is this amount? How many hydrogen molecules will this result?

1. Let’s compose the equation of chemical interaction.

Fe + H2SO4 = FeSO4 + H2.

2. Let’s find the amount of iron, and then by the reaction equation of the amount of sulfuric acid and hydrogen.

n (Fe) = m (Fe) / M (Fe) = 10.2 g / 56 g / mol = 0.182 mol.

n (H2SO4) = n (Fe) = 0.182 mol.

n (H2) = n (Fe) = 0.182 mol.

3. Let’s find the volume of the formed hydrogen and the number of its molecules.

V (H2) = n (H2) * Vm = 0.182 mol * 22.4 L / mol = 4.08 L.

N (H2) = n (H2) * NA = 0.182 mol * 6.02 * 10 ^ 23 mol-1 = 1.0965 * 10 ^ 23.

Answer: n (H2SO4) = 0.182 mol; V (H2) = 4.08 L; N (H2) = 1.0965 * 10 ^ 23.



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