What volume of hydrogen is formed by the interaction of 12 grams of magnesium with 60 grams of hydrochloric acid.

Magnesium dissolves in acetic acid solution. The reaction is described by the following chemical equation:

Mg + 2CH3COOH = Mg (CH3COO) 2 + H2 ↑;

Let’s determine the molar amount of acetic acid.

To do this, divide its weight by the weight of 1 mole of acid.

M CH3COOH = 12 x 2 + 16 x 2 + 4 = 60 g / mol;

N CH3COOH = 60/60 = 1 mol;

It will be obtained in two times less amount of hydrogen and spent twice as minimal amount of metallic magnesium. That is, no more than 0.5 mol.

Find the available amount of magnesium.

M Mg = 24 grams / mol; N Mg = 12/24 = 0.5 mol;

Therefore, the acid is taken in excess.

Let’s calculate the volume of hydrogen.

For this purpose, we multiply the amount of substance by the volume of 1 mole of gas (filling volume 22.4 liters).

V H2 = 0.5 x 22.4 = 11.2 liters;