What volume of hydrogen is formed by the interaction of 2.7 g of aluminum containing 10% impurities with

What volume of hydrogen is formed by the interaction of 2.7 g of aluminum containing 10% impurities with the required amount of hydrochloric acid? How many is this?

Aluminum reacts violently with hydrochloric acid. In this case, an aluminum chloride salt can be obtained and hydrogen gas bubbles are released. The reaction is described by the following equation.

Al + 3HCl = AlCl3 + 3/2 H2;

Let’s determine the chemical amount of aluminum. To do this, we divide its weight by the molar weight of the substance.

M Al = 27 grams / mol;

N Al = 2.7 x 0.9 / 27 = 0.09 mol;

The chemical amount of released hydrogen will be: 0.09 x 3/2 = 0.135 mol

Let’s find its volume.

For this purpose, we multiply the chemical amount of the substance by the volume of 1 mole of gas (filling the space with a volume of 22.4 liters).

V H2 = 0.135 x 22.4 = 3.024 liters;