What volume of hydrogen is formed by the interaction of 200 g of iron containing 20%

What volume of hydrogen is formed by the interaction of 200 g of iron containing 20% of impurities with hydrochloric acid?

To solve, we write down the equation:
1. Fe + 2HCl = FeCl2 + H2 – OBP, hydrogen is released;
2. Calculations by formulas:
M (Fe) = 55.8 g / mol;
M (H2) = 2 g / mol;
m (Fe) = 200 * (1 – 0.20) = 160 g (mass without impurities).
3. Find the amount of the original substance:
Y (Fe) = m / M = 160 / 55.8 = 2.86 mol;
Y (H2) = 2.86 mol since the amount of substances according to the equation is 1 mol.
4. Determine the volume of the product:
V (H2) = 2.86 * 22.4 = 64 liters.
Answer: Hydrogen was obtained with a volume of 64 liters.