What volume of hydrogen is formed by the interaction of 250 g of a solution of 30%

What volume of hydrogen is formed by the interaction of 250 g of a solution of 30% sulfuric acid with zinc, if the yield of the reaction product is 95%?

Zinc metal reacts with sulfuric acid to release hydrogen gas and form zinc sulfate. The reaction is described by the following equation:

Zn + H2SO4 = ZnSO4 + H2;

1 mole of metal reacts with 1 mole of acid. This synthesizes 1 mol of salt and 1 mol of hydrogen.

Let’s calculate the amount of sulfuric acid.

M H2SO4 = 2 + 32 + 16 x 4 = 98 grams / mol;

N H2SO4 = 250 x 0.3 / 98 = 0.765 mol;

During the reaction, 0.765 x 0.95 = 0.727 mol of hydrogen will be synthesized. Let’s calculate its volume.

To do this, we multiply the amount of substance by the volume of 1 mole of gas.

V H2 = 0.727 x 22.4 = 16.285 liters;