What volume of hydrogen is formed by the interaction of 6.5 g of zinc with the required amount of hydrochloric acid?

When dissolved in hydrochloric acid, metallic zinc is converted to zinc chloride. Zinc is a bivalent metal. Therefore, during the reaction, it interacts with double the amount of hydrogen chloride. This synthesizes a single chemical amount of zinc chloride. The reaction is described by the following chemical reaction equation:

Zn + 2HCl = ZnCl2 + H2;

Let’s calculate the molar amount of metallic zinc. To do this, we divide its weight by the mass of 1 mole of metal.

N Zn = 6.5 / 65 = 0.1 mol;

With this amount of zinc, 0.2 mol of acid will react. This will synthesize 0.1 mol of hydrogen. Let’s calculate its volume. To do this, multiply the amount of substance by the volume of 1 mole of gas (22.4 liters).

V H2 = 0.1 x 22.4 = 2.24 liters;