What volume of hydrogen is formed by the interaction of 650 grams of zinc

What volume of hydrogen is formed by the interaction of 650 grams of zinc, containing 20% of impurities, with the required amount of hydrochloric acid? What is this amount of substance?

1. We make a chemical equation, not forgetting to put down the coefficients:

Zn + 2HCl = ZnCl2 + H2.

2. Find the mass fraction of Zn:

ω (Zn) = 100% – ω (Zn impurities) = 100% – 20% = 80% (0.8).

3. Find the mass Zn:

m (Zn) = m (Zn impurities) * ω (Zn) / 100% = 520g.

4. Find the amount of substance Zn:

n (Zn) = m (Zn) / M (Zn) = 520g / 65 g / mol = 8 mol.

5. From the equation you can see:

n (Zn) = n (H2) = 8 mol.

6. Find the volume of hydrogen:

V (H2) = n (H2) * Vm = 8 mol * 22.4 l / mol = 179.2 l.

Answer: V (H2) = 179.2 liters.