What volume of hydrogen is formed by the interaction of 650 mg of zinc containing 20%

What volume of hydrogen is formed by the interaction of 650 mg of zinc containing 20% impurities with an excess of hydrochloric acid?

The reaction of zinc with hydrochloric acid is described by the following chemical reaction equation.

Zn + 2HCl = ZnCl2 + H2;

One mole of zinc reacts with two moles of hydrochloric acid. This produces one mole of hydrogen.

The mass of pure zinc will be 0.65 x 0.8 = 0.52 grams.

Let’s determine the amount of the substance contained in 0.52 grams of zinc.

M Zn = 65 grams / mol;

N Zn = 0.52 / 65 = 0.008 mol;

0.008 mol of zinc will react with 0.016 mol of hydrochloric acid. This produces 0.008 mol of hydrogen.

One mole of ideal gas under normal conditions takes a volume of 22.4 liters.

Let’s determine the volume of hydrogen.

V H2 = 0.008 x 22.4 = 0.1792 liters;