What volume of hydrogen is formed if aluminum with the amount of a substance of 1.24 mol reacts with hydrochloric acid?

Metallic aluminum interacts with hydrochloric acid. In this case, an aluminum chloride salt can be obtained and hydrogen gas bubbles are released. The reaction is described by the following equation.

Al + 3HCl = AlCl3 + 3/2 H2;

N Al = 1.24 mol;

The chemical amount of released hydrogen will be: 1.24 x 3/2 = 1.86 mol

Let’s calculate its volume.

To do this, multiply the chemical amount of the substance by the volume of 1 mole of gas (filling a space with a volume of 22.4 liters).

V H2 = 1.86 x 22.4 = 41.66 liters;