What volume of hydrogen is formed when 130 mg of zinc containing 20% impurities is dissolved in hydrochloric acid?

The interaction of zinc with any acid, for example with hydrogen chloride, occurs in accordance with the following chemical reaction equation:

Zn + 2HCl = ZnCl2 + H2;

Regardless of the type of acid, dissolving 1 mole of metal releases 1 mole of gaseous hydrogen.

The mass of pure zinc will be 130 x 0.8 = 104 milligrams.

Let’s calculate the amount of substance contained in a sample of 104 milligrams of metal.

To do this, we find the ratio of its weight to molar mass.

N Zn = 104/1000/65 = 0.0016 mol;

The same amount of hydrogen will be released during this interaction.

Let’s calculate its volume.

One mole of gas under normal conditions fills a volume of 22.4 liters.

The volume of hydrogen will be:

V H2 = 0.0016 x 22.4 = 0.03584 liters;