What volume of hydrogen is formed when 325 g of zinc containing 20% impurities are dissolved in hydrochloric acid?

The reaction of zinc with hydrochloric acid is described by the following chemical reaction equation:

Zn + 2HCl = ZnCl2 + H2;

In accordance with the coefficients of the chemical equation, dissolving one mole of zinc releases one mole of hydrogen.

Let’s determine the amount of substance in 325 grams of zinc.

M Zn = 65 grams / mol;

N Zn = 325/65 = 5 mol;

Let us determine the volume of 5 mol of hydrogen.

One mole of ideal gas under normal conditions takes a volume of 22.4 liters.

V H2 = 5 x 22.4 = 112 liters;