What volume of hydrogen is generated by the interaction of 6.5 g of zinc.

What volume of hydrogen is generated by the interaction of 6.5 g of zinc. containing 10% impurities, with the required amount of sulfuric acid?

The reaction of zinc with sulfuric acid is described by the following chemical reaction equation:

Zn + H2SO4 = ZnSO4 + H2;

In accordance with the coefficients of the chemical equation, dissolving one mole of zinc releases one mole of hydrogen.

The mass of pure zinc will be 6.5 x 0.9 = 5.85 grams;

Let’s determine the amount of substance in this mass.

M Zn = 65 grams / mol;

N Zn = 5.85 / 65 = 0.09 mol;

Let us determine the volume of 0.09 mol of hydrogen.

One mole of ideal gas under normal conditions takes a volume of 22.4 liters.

V H2 = 0.09 x 22.4 = 2.016 liters;