What volume of hydrogen is released when 5.4 grams of aluminum is dissolved in a sulfuric acid solution?

We compose the reaction equation:
2Al + 3H2SO4 = Al2 (SO4) 3 + 3H2
M (Al) = 2 * 27 = 54 g / mol
Vm (H2) = 3 * 22.4 = 67.2 L / mol
Through the proportion, we find the released gas
5.4 / 54 = x / 67.2
x = 5.4 * 67.2 / 54 = 6.72 liters



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