What volume of hydrogen sulfide is formed by the interaction of 10.4 g of technical iron sulfide

What volume of hydrogen sulfide is formed by the interaction of 10.4 g of technical iron sulfide containing 15% of impurities?

1. We make a chemical equation, not forgetting to put down the coefficients:

FeS + H2SO4 = FeSO4 + H2S.

2. Find the mass of impurities:

m (impurities) = m * ω = 44 * 0.04 = 1.76g.

3. Find the mass of pure sulfide:

m (pure) = 44 – 1.76 = 42.24g.

4. Let’s find the amount of the substance FeS:

n (FeS) = m / M = 42.24 / 88 = 0.48 mol; and the equation shows: n (FeS) = n (H2S).

5. Let’s find the volume of H2S:

V (H2S) = n * Vm = 0.48 * 22.4 = 10.75L.

Answer: V (H2S) = 10.75L.