What volume of hydrogen will be obtained by the interaction of 230 g of sodium with water?

Decision:

Let’s compose the equation for the reaction of interaction of sodium with water:
2Na + 2H2O = 2NaOH + H2;

The molecular weight of sodium is 23 g / mol. Let’s calculate the amount of substance in sodium:
230/23 = 10 mol;

There is a factor 2 times lower before hydrogen than before sodium. This means that the amount of substance in hydrogen is 5 mol. Let’s find the volume of the resulting hydrogen:
22.4 * 5 = 112 liters;

Answer: the volume of hydrogen is 112 liters.