What volume of hydrogen will be obtained by the reaction of 12 g of magnesium with hydrochloric acid?

The reaction of magnesium with hydrochloric acid is described by the following chemical reaction equation.

Mg + 2HCl = MgCl2 + H2;

When one mole of magnesium is dissolved, one mole of hydrogen is formed.

Let’s determine the amount of substances.

M Mg = 24 grams / mol;

N Mg = 12/24 = 0.5 mol;

N H2 = N Mg = 0.5 mol;

One mole of ideal gas under normal conditions takes a volume of 22.4 liters.

The volume of hydrogen will be.

V H2 = 0.5 x 22.4 = 11.2 liters;