What volume of hydrogen will be obtained by the reaction of phenol weighing 200 g (ppm 30%) with potassium?

Given:
m solution (C6H5OH) = 200 g
ω (C6H5OH) = 30%
Find: V (H2) -?
1) Write the reaction equation:
2C6H5OH + 2K => 2C6H5OK + H2 ↑;
2) Calculate the mass of C6H5OH:
m (C6H5OH) = ω (C6H5OH) * m solution (C6H5OH) / 100% = 30% * 200/100% = 60 g;
3) Calculate the amount of C6H5OH substance:
n (C6H5OH) = m (C6H5OH) / M (C6H5OH) = 60/94 = 0.64 mol;
4) Determine the amount of substance H2:
n (H2) = n (C6H5OH) / 2 = 0.64 / 2 = 0.32 mol;
5) Calculate the volume H2:
V (H2) = n (H2) * Vm = 0.32 * 22.4 = 7.2 liters.
Answer: The volume of H2 is 7.2 liters.