What volume of hydrogen will be released during the interaction of 100 g glycerin with 2.3 g sodium?

Given:
m (C3H5 (OH) 3) = 100 g
m (Na) = 2.3 g

To find:
V (H2) -?

1) Calculate the amount of glycerin substance:
n (C3H5 (OH) 3) = m / M = 100/92 = 1.09 mol;
2) Calculate the amount of sodium substance:
n (Na) = m / M = 2.3 / 23 = 0.1 mol;
3) Write the reaction equation:
2C3H5 (OH) 3 + 2Na => 2C3H5 (OH) 2ONa + H2 ↑;
4) Determine the amount of hydrogen substance:
n (H2) = n (Na) / 2 = 0.1 / 2 = 0.05 mol;
5) Calculate the volume of hydrogen:
V (H2) = n * Vm = 0.05 * 22.4 = 1.12 liters.

Answer: The volume of H2 is 1.12 liters.